Question

The area of the parallelogram abcd is 90cm^2 find ar(abef) ,ar(abd), ar(bef)

Answer 1

you are not attached pic ,
well, it's okay I solved the question , I hope it will help you.

area of given ABCD parallelogram is 90 cm.

(i) area of rectangle ABEF = area of parallelogram ABCD
because , one common side is AB of parallelogram and rectangle and hight of both parallelogram is same as Breadth of rectangle .
hence, area of rectangle ABEF = 90 cm²

(ii) area of ABD = half of area of parallelogram { see attachment it is clear that , diagonal is divided by two equal of parallelogram, here BD is diagonal , that's why are(ABD) = ar(ABCD)/2 }
hence, ar(ABD) = 90cm²/2 = 45 cm²

(iii) ar(BEF) = half of ar(ABEF) = 45 cm² [ similarly diagonal of rectangle divide its two equal part ]

Answer 2

ar(ADEF)=ar(ABCD)

ii.ar(ABD)=1/2ar(ABEF)

=1/2×90

=90/2

=45

iii.ar(BEF)=1/2ar(ABEF)

=1/2×90

=90/2

=45