The area of the parallelogram is p cm² and the height is q cm. A second parallelogram has equal area but base is r cm more than that of the first. Obtain an expression in terms of p, q and r for the height h of the second parallelogram.
raji22:
hiiii
all r answered broo
u can trll
tell
Answers
Answered by
1
The expression is pq=(p+2r)*h
Answered by
0
Let the base of the first triangle be 'b' cm.
b×q=p²____(1)
Also, base of 2nd triangle =(b+r)
(b+r)h= p²
(p²/q+r)=p²
b×q=p²____(1)
Also, base of 2nd triangle =(b+r)
(b+r)h= p²
(p²/q+r)=p²
Similar questions