Question

The area of the parallelogram PQRS is 45. Find area of ΔPQR.​

Answer 1

Answer:

ABD and ABC lie on the same base AB and between the same parallels AB and DC.

ar (ABD) = ar (ABC)

Subtracting ar (AOB) from both sides,

ar (ABD) – ar (AOB)

= ar (ABC) – ar (AOB)

ar (AOD) = ar (BOC)

Answer 2

Given:-

• Area of Parallelogram PQRS = 45 sq. units.

To Find:-

• Area of ∆PQR.

Solution:-

Diagonal PR divides the parallelogram PQRS in to ∆PQR & ∆PSR

In ∆PQR & ∆PSR

→ PQ = RS {Opposite Side of a Parallelogram}

→ QR = PS {Opposite Sides of a Parallelogram}

→ PR = PR {Common Side}

∆PQR ≅ ∆PSR

WKT, Congruent Triangles have equal area

Area of ∆PQR = area of PQRS÷2

→ 45/2

→ 22.5 sq. units

Therefore, Area of ∆PQR ☞ 22.5 sq. units.

$\Large{✓}$

Hope It Helps You ✌️