The area of the parallelogram whose diagonalsare along vectors 8i-6j and 3i+4j-12k
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7
Answer:
65
Step-by-step explanation:
Area of the parallelogram whose diagonals are given by d₁ and d₂
is given by |d₁ × d₂|/2.
d₁ = 8i-6j, d₂ = 3i+4j-12k
d₁ × d₂ = 72i + 96j + 50k
|d₁ × d₂| = 130
Area of parallelogram = 130/2 = 65 sq. units.
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