Question

The area of the parallelogram whose length is 3 cm, width is 2 cm and one diagonal 4cm is-

Answer 1

Let in ΔABC,

a = 2 cm, b = 3 cm, c = 4 cm

s = a+b+c/2 = 2+3+4/2 = 9/2 = 4.5 cm

Ar. = √4.5(4.5-2)(4.5-3)(4.5-4)

= √4.5*2.5*1.5*0.5

= 1/100√45*25*15*5

= 1/100√3*3*5*5*5*3*5*5

= 3*5*5/100√3*5

= 75/100√15

= 3/4√15

Area of ║gm = 2*area of ΔABC = 2*3/4√15

= 3/2√15 cm²

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