The area of the pistons in a hydraulic machine are 5cm² and 625cm². What force on the smaller piston will support a load of 1250N on the larger piston?
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The areas of the pistons in a hydraulic machine are 5 cm2 and 625cm2 what force on the smaller piston will support a load of 1250 N on the larger piston state any assumption which you make in your calculation. ... A1 = 5CM2 = 5/10000 M2. A2 =625 CM2= 625 /10000M2.
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