Question

The area of the plate of a parallel plate capacitor is
100 cm² and the distance between the plates is 1 mm
On connecting the capacitor with a battery of 120 V a
charge of 0.12 uC is stored. Find the dielectric constant
of the substance filled between the plates.​

Answer 1

Answer:

The capacitance of the capacitor is

0.12muC)/(120V) = 1.0 X 10^(-9) F

. If Kbe the dielectric constant, the capacitance is also given by (Kepsion_0A)/(d). Thus, (Kx 8.85 X 10^(-12) Fm(-1) X 100 X 10(-4) m^2)/(1.0X10^(-3) m) = 1.0 X 10^(-9) F

or , K = 11.3