The area of the point tip of pin 0.01cm^2 .Your pushing force on the head of the pin is 20N. Find pressure?
KunalTheGreat:
no spam pls.
Answers
Answered by
12
#AlexaRousey here!!
Given :
Area = 0.01 cm^2
= 0.01 * 10^-4 m^2
= 10^-6 m^2
Force = 20N
Pressure = F/A
= 20/10^-6 Pa
= 20* 10^6 Pa
= 2 * 10^7 Pa
Thanks!!
Given :
Area = 0.01 cm^2
= 0.01 * 10^-4 m^2
= 10^-6 m^2
Force = 20N
Pressure = F/A
= 20/10^-6 Pa
= 20* 10^6 Pa
= 2 * 10^7 Pa
Thanks!!
Answered by
5
Applied force = 20N
Area = 0.01cm² = 0.01/10000 m²
Pressure
= Force/Area
= 20x1000/0.01
= 20000000 N/m²
i.e.,2x10^7 N/m²
Area = 0.01cm² = 0.01/10000 m²
Pressure
= Force/Area
= 20x1000/0.01
= 20000000 N/m²
i.e.,2x10^7 N/m²
Similar questions
English,
7 months ago
Computer Science,
7 months ago
English,
7 months ago
English,
1 year ago
English,
1 year ago