Question

the area of the rectangle is 102sq.cm.
if it's length is 17cm,what is it's perimeter?​

Answer 1

Answer:

46 cm

Step-by-step explanation:

Area of a rectangle = l × b

102 sq.cm = 17 cm × b

= 17 cm × 6 cm

So, length = 17 cm, breadth = 6

Now find the perimeter of the rectangle

Perimeter of the rectangle = 2(l + b)

= 2(17 + 6) cm

= 2(23) cm

= 46 cm

Answer 2

Analysis→

Here we're given that the area of a rectangle is 102cm². And it's length is 17cm. And we've to find its perimeter. But to find the perimeter, first we've to find its breadth. And we know that:-

$\hookrightarrow\rm Area_{rectangle}=l\times b$

$\hookrightarrow\rm perimeter_{rectangle}=2(l+b)$

Given→

• Area of rectangle=102cm²
• Length of rectangle=17cm

To Find→

Perimeter of the rectangle.

Answer→

First let's find the breadth of the rectangle.

$\large{\underline{\boxed{\purple{\leadsto{\rm{Area_{rectangle}=l\times b}}}}}}$

$\implies\rm{Area_{rectangle}=l\times b}$

$\implies\rm{102cm^2=17cm\times b}$

$\implies\rm{b=\cfrac{102cm^2}{17cm}}$

$\implies\rm{b=\cfrac{\cancel{102cm^2}}{\cancel{17cm}}}$

$\implies\bf{b=6\checkmark}$

Now let's find the perimeter of the rectangle.

$\large{\underline{\boxed{\pink{\leadsto{\rm{Perimeter_{rectangle}=2(l+b)}}}}}}$

$\implies\rm{Perimeter_{rectangle}=2(l+b)}$

$\implies\rm{P=2(17cm+6cm)}$

$\implies\rm{P=2(23cm)}$

$\implies\rm{P=46cm}$

${\boxed{\boxed{\implies{\bf{P=46cm\checkmark}}}}}$

☞ Hence the perimeter of the rectangle is 46cm which is the required answer.

HOPE IT HELPS.