Question

the area of the rectangle is 117 cm2 and its breadth is 9 cm find its perimeter​

Answer 1

Question:-

the area of the rectangle is 117 cm² and its breadth is 9 cm find its perimeter

Answer:-

• The perimeter of rectangle is 44 cm.

To find:-

• Perimeter of rectangle

Solution:-

• Area of rectangle = 117 cm²
• Breadth of rectangle = 9 cm

As we know,

$\boxed{ \large{ \mathfrak{area = l \times b}}}$

Where,

• l = length of rectangle
• b = breadth of rectangle

According to question,

$\large{ \tt : \implies \: \: \: \: \: \: l \times 9 = 117}$

$\large{ \tt : \implies \: \: \: \: \: \: l = \frac{117}{9} }$

$\large{ \tt : \implies \: \: \: \: \: \: l = 13 \: cm}$

• The length of rectangle is 13 cm.

Now, we have to find the perimeter

$\large{ \boxed{ \mathfrak{perimeter = 2(l + b)}}}$

Where,

• l = length of rectangle
• b = breadth of rectangle

According to question,

$\large{ \tt : \implies \: \: \: \: \: \: perimeter = 2(13 + 9)}$

$\large{ \tt : \implies \: \: \: \: \: \: perimeter = 2 \times 22}$

$\large{ \tt : \implies \: \: \: \: \: \: perimeter = 44}$

Hence,

The perimeter of rectangle is 44 cm.

Answer 2

Given

• The area of the rectangle is 117cm².
• Breadth = 9cm

⠀

To find

• Perimeter of the rectangle.

⠀

Solution

• Let the length of the rectangle be l.

⠀

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large l }\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 9 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

⠀

• We know that

$\large{\boxed{\boxed{\sf{Area_{(Rectangle)} = Length \times Breadth}}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = 117}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {l \times b = 117}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {l \times 9 = 117}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {l = \dfrac{117}{9}}$

⠀

$\bf:\implies\: \: \: \: \: \: \: \: {l = 13}$

⠀

• We have b = 9cm and l = 13cm.

⠀

$\: \: \: \: \: \: \: \: \:\underline{\sf{\red{Finding\: Perimeter\: of\: the\: rectangle}}}$

⠀

$\large{\boxed{\boxed{\sf{Perimeter_{(Rectangle)} = 2(l + b)}}}}$

⠀

$\tt\longmapsto{Perimeter = 2(13 + 9)}$

⠀

$\tt\longmapsto{Perimeter = 2 \times 22}$

⠀

$\bf\longmapsto{Perimeter = 44}$

⠀

Hence,

• The perimeter of the rectangle is 44cm.

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