Question

the area of the rectangle is 117 cm2 and its breadth is 9 cm find its perimeter​

Answer 1

★Required AnswEr:

• The required perimeter of the rectangle = 44cm

★ Given:

• The area of the rectangle is 117 cm² and its breadth is 9 cm.

★ Need To Find Out:

• The required perimeter of the rectangle = ?

★ Required Solution:

Formula used here:

• Area of the rectangle = Length × Breadth

Putting the values:

=> 117 = length × 9

=> Length = 117/9

=> Length = 13 cm

Hence:

• Length of the rectangle = 13 cm

_____________________

Again, formula used here:

• Perimeter of the rectangle = 2 × (Length + Breadth)

Putting the values:

Perimeter of rectangle = 2× (13 cm + 9 cm)

=> Perimeter of the rectangle = 2 × (22cm)

=> Perimeter of the rectangle = 44 cm

Therefore:

• The required perimeter of the rectangle is 44 cm.

Answer 2

Given : The area of the rectangle is 117cm² & Breadth = 9cm.

To Find : Find the perimeter of the rectangle ?

_________________________

Solution : Let the length of the rectangle be l.

$~$

$\underline{\frak{As~ we ~know ~that~:}}$

• $\boxed{\sf\pink{Area_{Rectangle}~=~Length~×~Breadth}}$

$~$

$\qquad{\sf:\implies{Area~ = ~117}}$

$\qquad:{\sf:\implies{l ~\times ~b~ = ~117}}$

$\qquad{\sf:\implies{l~ \times ~9 =~ 117}}$

$\qquad{\sf:\implies{l~ = ~\cancel\dfrac{117}{9}}}$

$\qquad:\implies{\underline{\boxed{\frak{\purple{l ~= ~13}}}}}$★

$~$

Therefore,

• We have b = 9 cm & l = 13 cm.

$~$

◗Finding Perimeter of the Rectangle :

$~$

$\underline{\frak{As~ we ~know ~that~:}}$

• $\boxed{\sf\pink{Perimeter_{Rectangle}~=~2(l~+~b)}}$

$~$

$\qquad{\sf:\implies{Perimeter~=~2(13~+~9)}}$

$\qquad{\sf:\implies{2~×~22}}$

$\qquad:\implies{\underline{\boxed{\frak{\pink{Perimeter~=~44}}}}}$★

$~$

Hence,

$\therefore\underline{\sf{The ~perimeter ~of ~the~ rectangle~ is~\bf{\underline{44~cm}}}}$