the area of the rectangle is 192 cm and it's perimeter is 56 cm find the dimension of the rectangle
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Answer:
14cm,14cm
Step-by-step explanation:
2(L+B)=56. LB=196
L+B = 28. (i) L = 196/B (ii)
By putting the value of L in (i)
196/B+B=28
= (196+B²)/B = 28
= 196+B²=28B
= B²-28B+196=0
= B²-14B-14B+196=0
= B(B-14)-14(B-14)=0
= (B-14)(B-14)=0
= (B-14)²=0
= √(B-14)²=√0
= B-14=0
= B= 14 cm (ANS)
Now putting value of B in (i)
L+14=28
L=14 cm (ANS)
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