Math, asked by mahadevaswamy2843, 1 month ago

The area of the rectangle is 338sq.cm. If the breadth of the rectangle is double of the length. Find the perimeter of the rectangle.
A) 78 Sq.cm B) 78 cm
C) 39 Sq.cm D) 39 cm​

Answers

Answered by itsRakesh
0

Answer:

78 sq. cm

Step-by-step explanation:

Length = x

Breadth = 2x

Area = 2x*x = 2(x^2)

=> 2(x^2) = 338

=> x^2 = 338/4 = 169

=> x = sqrt(169) = 13

=> Perimeter = 2(Length+breadth)

=> 2(2x+x)

=> 2(3x)

=> 6x

=> 6*13

=> 78 sq. cm

Answered by sumit83610
1

Answer:

Let the length be x and breadth be 2x

x(2x)=338\\x^{2} =169\\x=13\\Perimeter=2(l+b)\\=2(13+26)\\=78 cm

pls mark brainliest

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