Question

The area of the rectangle is 3x2 + 7x - 6, what is the length if the width is
(x + ​3)​

Answer 1

Answer:

$therefore \:length = (3x - 2)$

Step-by-step explanation:

$area= 3 {x}^{2} + 7x - 6 \\ = 3 {x}^{2} + 9x - 2x - 6 \\ = 3x(x + 3) - 2(x + 3) \\ = (3x - 2)(x + 3) \\ \\ if \: width = (x + 3) \\ therefore \:length = (3x - 2)$

Answer 2

Given:

The area of the rectangle is $3x^{2} +7x-6$

To Find:

what is the length if the width is  (x + ​3)​

Solution:

In this question, we can do the sum in many ways like factorizing the area of dividing it by (x+3) using the long division method but going the normal way we will solve it by factorizing the area

$3x^{2} +7x-6$

To factorize the equation we will split the middle tern as 9x-2x then it will be easy for us to factorize we split the tern using -6*3=-18then 9*-2=-18 so proceeding further

$=3x^{2} +9x-2x-6\\=3x(x+3)-2(x+3)\\=(x+3)(3x-2)$

Now we know the formula of the area is length times breadth and here we can see the width is (x+3) so the length will be the other value that is (3x-2)

Hence, the length if the width is (x+3) will be(3x-2).