Question

The area of the rectangle is 49 sq. cm. &
its breadth is 2.8 cm. Find the length of
the rectangle.


answer fast I'll mark it as brainliest and rate 5​

Answer 1

Given :

• The area of the rectangle is 49cm² and its breadth is 2.8cm.

To Find :

• Length of the rectangle.

Solution :

Here

• Area of the rectangle = 49cm²
• Breadth of the rectangle = 2.8cm

We've to find the length of the rectangle.

As we know that

• Area of a rectangle = l × b

Where

• l = length
• b = breadth

According to question :

→ Area of rectangle = l × b

→ 49 = l × 2.8

→ l = 49/2.8

→ l = 17.5

Hence,

• The length of the rectangle = 17.5cm.

Answer 2

Given:-

• Area of the rectangle is 49 cm².
• Breadth of the rectangle is 2.8 cm.

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To find:-

• Length of the rectangle.

⠀

Solution:-

★Formula used:-

$\star{\boxed{\sf{\orange{Area\: of\: rectangle = Length \times Breadth}}}}$

⠀

$\large{\tt{\longmapsto{49 = Length \times 2.8}}}$

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$\large{\tt{\longmapsto{Length = \dfrac{49}{2.8}}}}$

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$\large{\tt{\longmapsto{\boxed{\red{Length = 17.5\: cm}}}}}$

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Hence, the length of the rectangle is 175 cm.

⠀

⠀

Diagram:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 175 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 2.8 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$