The area of the rectangle is 52m2 and its breadth is 6.5m.Find the length and perimeter of the rectangle
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Answered by
7
Area of a rectangle=( length) (breadth) =52m^2
Length of the Rectangle=
Area/Breadth=52/6.5=8
Perimeter of a rectangle=2(length+breadth) =2(6.5+8)=2(14.5)=29
Length of the Rectangle=
Area/Breadth=52/6.5=8
Perimeter of a rectangle=2(length+breadth) =2(6.5+8)=2(14.5)=29
Answered by
6
given
breadth of rectangle=6.5m
let length be= cm
area of rectangle =l×b
52 =6.5×x
52/6.5 =x
8 =x
therefore length of rectangle= 8m
perimeter of rectangle=2(L+b)
=2(8+6.5)
=2(14.5)
=29.0m
hope it helped u
breadth of rectangle=6.5m
let length be= cm
area of rectangle =l×b
52 =6.5×x
52/6.5 =x
8 =x
therefore length of rectangle= 8m
perimeter of rectangle=2(L+b)
=2(8+6.5)
=2(14.5)
=29.0m
hope it helped u
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