Question

The area of the rectangle is 90cm.sq and it’s 30cm long finds it’s breadth

Answer 1

Answer:

B=3 cm

Step-by-step explanation:

Length of rect.= 30cm

Breadth of rect.=B cm

Area of rect. = 90 cm ^2

L×B =90 cm^2

30× B =90

B =90/30

B = 3cm

Answer 2

$\frak{Given} = \begin{cases} &\sf{The\:area\:of\:the\:rectangle\:=\:90cm^{2}.} \\\\\\\\\\\\ &\sf{Length\:=\:30cm}\end{cases}$

To find:-    

• Breadth of the rectangle .

Solution:-      

$\maltese$ Here we have area of the rectangle and length of the rectangle . to find the breadth , firstly we will let the breadth be x and then by applying the formulae ( Area of the rectangle =  Length × Breadth we will get the answer .

• $\maltese$ Let the breadth be = x

$\sf{\longmapsto\:Area\:of\:the\:rectangle\:=\:Length\:\times\:Breadth\:}$

$\sf{\longmapsto\:90\:=\:30\:\times\:x\:}$

$\sf{\longmapsto\:\dfrac{90}{30}\:=\:x}$

$\sf{\longmapsto\:3\:=\:x}$

$\color{navy}{\underline{\sf{Therefore\:the\:breadth\:of\:the\:rectangle\:is\:3\:cm\:.}}}$

Some More Formulas:-

$\sf{\longmapsto\:Area\:of\:the\:rectangle\:=\:Length\:\times\:Breadth\:}$

$\sf{\longmapsto\:Area\:of\:the\:square\:=\:a^{2}}$

$\sf{\longmapsto\:Area\:of\:the\:circle\:=\:\pi r^{2}}$

$\sf{\longmapsto\:Peremiter\:of\:the\:Square\:=\:4a}$

$\sf{\longmapsto\:Perimeter\:of\:the\:rectangle\:=\:2\:(L\:+B\:)}$