Question

The area of the rectangle is x square + 7x + 10. If the length is (x+5), then find its breadth.​

Answer 1

Answer:

x+2

Step-by-step explanation:

${x}^{2} + 7x + 10 = {x}^{2} + 5x + 2x + 10$

$= (x + 5)(x + 2)$

since area of rectangle is l×b

therefore breadth is x+2

Answer 2

Answer:

$\bf\fbox\purple{BREADTH of the rectangle is ( x + 2)}$

Step-by-step explanation:

Given:-

Area of rectangle = x² + 7x +10

Length = ( x + 5)

Solution :-

$Area \: of \: rectangle = x² + 7x +10 \\ \\ l \times b = {x}^{2} + 7x + 10 \\ \\ (x + 5) \times b = {x}^{2} + 7x + 10 \\ \\ b = \frac{ {x}^{2} + 7x + 10}{x + 5} \\ \\ b = \frac{ {x}^{2} + 5x + 2x + 10 }{x + 5} \\ \\ b = \frac{x(x + 5) + 2(x + 5)}{x + 5} \\ \\ b = \frac{( x+ 5)(x + 2)}{ x + 5} \\ \\ b = (x + 2)$

Hence the breadth of the rectangle is ( x + 2)