Math, asked by ashliemae, 4 months ago

The area of the rectangle is
x2-100/8sq units while the length is 2x+20/20 units. find the width of the rectangle

Answers

Answered by roczerbala
2

Answer:

Step-by-step explanation:

Area of the rectangle = x² - 100/8 sq.units

L × B = x² - 100/8 sq.units

2x + 20/20 × B =  x² - 100/8 sq.units

B =  (x² - 100/8)/2x + 20/20

   =  [x² - 100/8]÷[2x + 20/20]

   =  [(x + 10)(x - 10)/4]÷[2(x + 10)/10]

   =  [x - 10/2]÷ [2(1)/5]

   =  [x - 10/2]×[5/2(1)]

   =  5[x - 10]/4

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