Question

The area of the rectangular field is 468 sq.m . If its length is 24m . Find the width and perimetre of the field

Answer 1

$\LARGE{\orange{\boxed{\orange{\underline{\blue{\underline{ \green{ \underline{\orange{\mathtt{Given:↓}}}}}}}}}}}$

The area of the rectangular field is 468²m. If its length is 24m.

$\LARGE{\red{\boxed{\red{\underline{\blue{\underline{ \green{ \underline{\red{\mathtt{Find:↓}}}}}}}}}}}$

Find the width and perimetre of the field.

$\LARGE{\blue{\boxed{\purple{\underline{\blue{\underline{ \green{ \underline{\blue{\mathtt{Answers:↓}}}}}}}}}}}$

Width = 19.5meters

Perimeter = 87 meters

$\LARGE{\green{\boxed{\green{\underline{\blue{\underline{ \red{ \underline{\green{\mathtt{Solution:↓}}}}}}}}}}}$

According to the question,

The area of the rectangular field is 468²m.

The length of the field is 24 m.

$\bold{\therefore \: \: The \: \: width \: \: of \: \: the \: \: field }$

We know,

That the area of a rectangle is:

$\large\bold{Length×Breath}$

So,

$\implies \bold {468 m \: \div 24m}$

$\Large \implies \bold \pink{ \boxed{Width = 19.5m}}$

$\bold{\therefore \: \: The \: \: perimeter \: \: of \: \: the \: \: field }$

$\implies \bold{(24m \times 2) + (19.5m \times 2)}$

$\implies \bold{48m + 39m}$

$\Large\implies \bold \red {\boxed{Perimeter = 87m}}$

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