Question

The area of the rectangular field is given as (3ac+2bc+3ad+2bd) sq.unit. Find the length of the field if the width is (3a+2b) units.​

Answer 1

Amit want to buy a rectangular field whose area is (3a2+5ab+2b2) sq. units. One of its sides is (a+b) units. Find the length of the fence around the field.

Area of  rectangular field =3a2+5ab+2b2

One of the side =a+b

Second side =a+b3a2+5ab+2b2=a+b(3a+2b)(a+b)=3a+2b 

Length of the fence around the field =2(l+b)

=2(3a+2b+a+b)

=2(4a+3b)

=8a+6b

Step-by-step explanation:

hope it's help u

Answer 2

Length of the field is (c + d) units if area of rectangular field is  (3ac+2bc+3ad+2bd) sq. unit and width is (3a + 2b)

Given:

The area of the rectangular field is given as (3ac+2bc+3ad+2bd) sq. unit

width is (3a+2b) units

To Find:

Length of the field

Solution:

Area of Rectangle = Length x width

Area = (3ac+2bc+3ad+2bd)

Step 1:

Take c common from 1st 2 terms and d from last 2 terms

Area = c(3a + 2b) + d(3a + 2b)

Step 2:

Take (3a + 2b)  common  

Area =  (3a + 2b)(c+ d)

Step 3:

Compare Area =  (3a + 2b)(c+ d)  with

Area = width  x  length

width = (3a + 2b) units given

Hence Length = (c + d) units

Length of the field is (c + d) units