Question

the area of the rectangular field is given by the expression y²-11y+30​.sq.m. Find the dimensions of the field​

Answer 1

Answer:

We have area of rectangle = ( y2 - 11 y + 30 ) m2 , So we use splitting the middle term method and get

= y2 - 6 y - 5 y + 30

= y ( y - 6 ) - 5 ( y - 6 )

= ( y - 5 ) ( y - 6 )

therefore,

Dimensions of rectangle = ( y - 5 ) m and ( y - 6 ) m ( Ans )

Answer 2

Answer:

Step-by-step explanation:

have area of rectangle = ( y2 - 11 y + 30 ) m2 , So we use splitting the middle term method and get

= y2 - 6 y - 5 y + 30

= y ( y - 6 ) - 5 ( y - 6 )

= ( y - 5 ) ( y - 6 )

therefore,

Dimensions of rectangle = ( y - 5