Math, asked by narayanh8443, 1 year ago

the area of the rectangular plot is 528 m square. the length of the plot is one meter more than twice its breadth.Find the length and breadth of the plot

Answers

Answered by pandaXop
6

Length = 33 m

Breadth = 16 m

Step-by-step explanation:

Given:

  • Area of rectangular plot is 528 m².
  • Length of plot is one meter more than twice the breadth.

To Find:

  • What is the length & breadth of plot?

Solution: Let the breadth of rectangular plot be x m. Therefore,

➛ Length = One meter more than twice breadth.

➛ Length = (2x + 1) m

As we know that

Area of Rectangle = ( Length \times Breadth )

A/q

  • Area = 528 m²

\implies{\rm } 528 = (2x + 1)(x)

\implies{\rm } 528 = 2x² + x

\implies{\rm } 0 = 2x² + x 528

Now, break the equation by middle term splitting.

➙ 2x² + x – 528

➙ 2x² – 32x + 33x – 528

➙ 2x (x – 16) + 33 (x – 16)

➙ (2x + 33) (x – 16)

➙ (2x + 33) = 0 or (x – 16) = 0

➙ 2x = –33 or x = 16

Since, x cannot be negative so we will take x = 16

Hence,

➫ Breadth = x = 16 m

➫ Length = 2x + 1 = 2(16)+1 = 33 m

_______________________

★ Verification ★

→ (Length) (Breadth) = 528 m²

→ (33) (16) m² = 528 m²

→ 528 m² = 528 m²

[ Verified ]

Answered by ButterFliee
6

GIVEN:

  • The area of the rectangular plot is 528 m square.
  • The length of the plot is one meter more than twice its breadth.

TO FIND:

  • What is the length and breadth of the plot ?

SOLUTION:

Let the length of the plot be 'l' m and breadth be 'b' m

If the length of the plot is one meter more than twice its breadth.

\bf{\dashrightarrow l = 2b + 1....1) }

We know that the formula for finding the area of the rectangular plot is:-

\large\bf{\star \: Area = Length \times Breadth \: \star}

According to question:-

Put the value of 'l' in formula

\rm{\dashrightarrow 528 = (2b+1)b }

\rm{\dashrightarrow 528 = 2b^2 + b }

\rm{\dashrightarrow 2b^2 + b - 528 = 0 }

\rm{\dashrightarrow 2b^2 +(33-32)b -528 = 0 }

\rm{\dashrightarrow 2b^2 + 33b - 32b - 528 = 0 }

\rm{\dashrightarrow b(2b + 33) -16(2b + 33) = 0}

\rm{\dashrightarrow (2b + 33)(b-16)=0 }

\rm{\dashrightarrow b = \dfrac{-33}{2} \: (Neglected) }

\bf{\dashrightarrow b = 16 \: m }

Put the value of 'b' in equation 1)

\rm{\dashrightarrow l = 2 \times 16+1 }

\rm{\dashrightarrow l = 32 +1 }

\bf{\dashrightarrow l =33 \: m }

Hence, the length and breadth of the rectangular plot are 33 m and 16 m respectively.

______________________

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