The area of the rectangular tiles need to be 64 squares in how many ways you can search tiles such that the length of the tile is greater than the breadth
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Length of a rectangular hall L=40 m
Breadth of the rectangular hall B=18 m
So, the area of hall
=L×B=40×18=720 m
2
Since,
Length of tiles l=1 m
Breadth of tiles b=50 cm=0.5 m
So, the area of each tile
=l×b=1×0.5=0.5 m
2
Therefore, the numbers of tiles are required
=
0.5
720
=1440
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