Question

The area of the rhombus is 128 sq.cm and the length of one diagonal is 32 cm . The length of the other diagonal is
12 cm or 4 cm or 20 cm or 8 cm ​

Answer 1

Step-by-step explanation:

area of rhombus=1/2*d1*d2

so here 128=1/2*32*d2

128=16*d2

d2=128/16

d2=8cm

Answer 2

Given :

• Area of Rhombus is 128 cm².
• One of its diagon is 32 cm.

To Find :

• Length of other Diagonal.

Solution :

$\longmapsto\tt{Let\:other\:diagonal\:be=x}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Rhombus=\dfrac{1}{2}\times{{d}_{1}}\times{{d}_{2}}}$

Putting Values :

$\longmapsto\tt{128=\dfrac{1}{{\cancel{2}}}\times{{\cancel{32}}}\times{x}}$

$\longmapsto\tt{128=16\times{x}}$

$\longmapsto\tt{\cancel\dfrac{128}{16}=x}$

$\longmapsto\tt\bf{x=8}$

So , The Length of other Diagonal is 8 cm..

_______________________

VERIFICATION :

$\longmapsto\tt{128=\dfrac{1}{2}\times{{d}_{1}}\times{{d}_{2}}}$

$\longmapsto\tt{128=\dfrac{1}{{\cancel{2}}}\times{32}\times{{\cancel{8}}}}$

$\longmapsto\tt{128=32\times{4}}$

$\longmapsto\tt\bf{128=128}$

HENCE VERIFIED