Question

The area
of the Rhombus is
28 m2. If its perimeter is 28cm
finds its altitude
​

Answer 1

Area of rhombus = 28m

2

Perimeter = 28m

All sides of a rhombus are equal.

∴4a=28

∴a=7m

Area of a rhombus = b×h

28=7×EC

∴EC=

7

28

=4m

∴EC=altitude=4m

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Answer 2

Altitude of Rhombus is 4m.

Given :

$\text{Area of Rhombus } = 28m^2$

$\text{Perimeter of Rhombus } = 28m$

Formula Applied :

$\text{Area of Rhombus } = b \times h$

$\text{Perimeter of Rhombus } = 4 a$

Solution :

As by given ,

perimeter of Rhombus = 28m.

As by formula,

perimeter of Rhombus = 4a

hence,

$4a = 28m \implies a = \frac{28}{4}$

$\boxed{a=7m}$

Diagram :

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,0)(1,0)(4,0) \put(1,-0.3){\bf A}\qbezier(4,0)(4,0)(5.8,2.5)\put(5.8,2.7){\bf C}\qbezier(5.8,2.5)(5.8,2.5)(2.8,2.5)\put(2.8,2.7){\bf D}\qbezier(1,0)(1,0)(2.8,2.5) \put(4,-0.3){\bf B} \qbezier(2.8,2.5)(2.8,2.5)(2.8,0)\put(3,1.2){\bf h} \put(2.5 ,-0.3){7m}\end{picture}$

Area of Rhombus  = $b\times h$

$\implies 28 m = b \times h$

$(bredth=side=a=7 m)$

$\implies 28 =7 \times h$

$\implies \frac{28}{7} = h$

$\boxed{h=4m}$

$height = altitude = 4 m$.

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