the area of the rhombus is 64sq cm of one diagonal is 16 then the other diagonal is ...?
k2w2:
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Answers
Answered by
1
using the formula p q / 2 solving for p = 2 and A/q forget this typing a equation with formula is just ok here the answer 8 cm .so p= 8 cm
Answered by
1
Hi ,
Let d1 and d2 are the two diagonals
of the Rhombus
d1 = 16cm
d2 = ?
Area of the Rhombus (A) = d1d2/2
According to the problem given,
A = 64 sqcm
d1d2/2 = 64
( 16 × d2 )/ 2 = 64
8 × d2 = 64
d2 = 64 / 8
d2 = 8 cm
I hope this helps you.
:)
Let d1 and d2 are the two diagonals
of the Rhombus
d1 = 16cm
d2 = ?
Area of the Rhombus (A) = d1d2/2
According to the problem given,
A = 64 sqcm
d1d2/2 = 64
( 16 × d2 )/ 2 = 64
8 × d2 = 64
d2 = 64 / 8
d2 = 8 cm
I hope this helps you.
:)
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