Question

The area of the right angled triangle is 62cm sq. If one of the sides containing right angle is 12.4 cm then find out the other sides

Answer 1

area of right angled triangle =0.5×b×h

62=0.5×b×12.4

therefore 62=6.2× b

therefore,62/6.2=base

therefore base = 10cm

other side:

By pythagorus theorem,

hypotenuse ^2=height ^2+base^2

= 12.4×12.4+10×10

=153.76+100

=253.76

therefore hypotenuse =15.92..

answer = 15.82 cm and

10 cm

Answer 2

Answer:

Step-by-step explanation:

In triangle ABC, angle B be the right angle.

So, AB (height) will be 12.4 cm.

AC will be the hypotenuse.

BC will be the base.

Ar(ABC) = 62

1/2 × BC × AB = 62

1/2 × BC × 12.4 = 62

BC = 10 cm.

AC^2 = AB^2 + BC^2 (Pythagoras Theorem)

AC^2 = (12.4)^2 + (10)^2

AC^2 = 153.76 + 100

AC^2 = 253.76

AC = √253.76

Here is your answer mate. Plz mark it as the brainliest answer. :-)