The area of the right angled triangle is 62cm sq. If one of the sides containing right angle is 12.4 cm then find out the other sides
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Answered by
12
area of right angled triangle =0.5×b×h
62=0.5×b×12.4
therefore 62=6.2× b
therefore,62/6.2=base
therefore base = 10cm
other side:
By pythagorus theorem,
hypotenuse ^2=height ^2+base^2
= 12.4×12.4+10×10
=153.76+100
=253.76
therefore hypotenuse =15.92..
answer = 15.82 cm and
10 cm
62=0.5×b×12.4
therefore 62=6.2× b
therefore,62/6.2=base
therefore base = 10cm
other side:
By pythagorus theorem,
hypotenuse ^2=height ^2+base^2
= 12.4×12.4+10×10
=153.76+100
=253.76
therefore hypotenuse =15.92..
answer = 15.82 cm and
10 cm
Answered by
5
Answer:
Step-by-step explanation:
In triangle ABC, angle B be the right angle.
So, AB (height) will be 12.4 cm.
AC will be the hypotenuse.
BC will be the base.
Ar(ABC) = 62
1/2 × BC × AB = 62
1/2 × BC × 12.4 = 62
BC = 10 cm.
AC^2 = AB^2 + BC^2 (Pythagoras Theorem)
AC^2 = (12.4)^2 + (10)^2
AC^2 = 153.76 + 100
AC^2 = 253.76
AC = √253.76
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