Question

The area of the sector of a circle of radius r/2 and central angle 2 theta is
Pls can someone help?

Answer 1

Answer:

let theta be x

area of sector =2x/360*22/7*r/2*r/2

=x/360*11/7*r^2

=11xr^2/2520

Answer 2

The area of sector is $A=\dfrac{\theta}{720}\pi r^2$.

Step-by-step explanation:

Given information:

Radius of the circle = r/2

Central angle = 2θ

We need to find the area of sector.

Formula for area of sector:

$A=\dfrac{\theta}{360}\pi r^2$

where, θ is central angle and r is radius.

Substitute θ=2θ and r=r/2 in the above formula.

$A=\dfrac{2\theta}{360}\pi (\dfrac{r}{2})^2$

$A=\dfrac{\theta}{180}\pi (\dfrac{r^2}{4})$

$A=\dfrac{\theta}{720}\pi r^2$

Therefore, the area of sector is $A=\dfrac{\theta}{720}\pi r^2$.

#Learn more

Find the area of the sector whose radius is 14 cm and making an angle of 60° at the center​.

https://brainly.in/question/8330984