the area of the sector of circle of radius and central angle theta is 1] 1/2 1.r 2] 2πr²∅/720 3] 2πr∅/360 4] πr∅/360
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Answer:
Given−
AOBisasectorofradius=randthecentralangle=θ.
Tofindout−
theperimeterofthesectorAOB=?
Solution−
ThearclengthAB=
360
o
θ
×2×π×r=
360
o
πθ
×2r.
Nowtheperimeterofthesector=OA+OB+arcAB
=r+r+ 360 oθ ×2πr=2r( 360 πθ+1).
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