The area of the shaded region of the rectangle is
p
q
(p, q are co-prime natural numbers) then p + q is ____________.
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.Area of rectangle = 8x5=40cm2 Area of other 2 parts:
1), Area of triangle = 1/2bh=7X4/2=14cm2. (1)
2) Area of triangle adjoining
base=hypoten use=v7^2+4^2 = 8.06
ht=1/2VI+I=v2/2=o.707
Area = 1/2bh=8.06xo.707/2=2.85 (2)
Total area=14+2.85 = 16.85cm2
Total area of triangles at the 2 sides
= 16.85x2=33.70cm2
AREA of SHADED PORTION
= Area of rectangle-Area of 4 triangles
= 40-33.70 = 6.30cm2. Ans
.
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