Question

The area of the square field is 36 m square. How long would it take for a bird to cross it diagonally flying at the rate of 30 under root 2 m per min.

Answer 1

Area of square =l^2

36=l^2

their for L=6m

Now,

By using pythagoras theorem,

h^2=p^2+b^2

h^2=6^2+6^2

h^2=36+36

h^2=72

h=6root under 2

Answer 2

Answer:

1/5 min = 12 sec

Step-by-step explanation:

Area of square =side^2

36 = side^2

$\sqrt{36}$ = side

6 m = side

Now,

By using pythagoras theorem,

diagonal^2=side^2+side^2

d^2=6^2+6^2

d^2=36+36

d^2=72

d=$\sqrt{72}$

d=$6\sqrt{2}$m

time = $\frac{distance}{speed}$

(distance = $6\sqrt{2}$ m; speed = $30\sqrt{2}$m/min)

time =( $\frac{6\sqrt{2} }{30\sqrt{2} }$ ) min

time = $\frac{1}{5}$  min

1/5 min = [(1/5) * 60]sec = 12 seconds