Question

the area of the square is x^2+8x+16 Sq units then find its side​

Answer 1

Answer:

(x+4)

Step-by-step explanation:

the formula for area of square is side^2

(a+b)^2 = a*a + 2*a*b + b*b

according to this identity

if we assume x as a, and then if we factorise it we can assume it as x*x

next if we assume 16 as b*b

then the equation will be b=√16

we will get value of b as 4

a=x

b=4

if we confirm this

then

(x+4) is side

area = side*side

(x+4)(x+4)

= x(x+4) + 4(x+4)

= (x^2 +4x) + (4x + 16)

= x^2 + (4+4)x +16

= x^2 + 8x + 16 = area

Answer 2

Answer: side is x+4 units

Step-by-step explanation:

x^2 + 8x + 16 units = area of square

area of square =side^2

side^2 = x^2 + 8x + 16

side = √x^2 + 8x + 16

       = √x^2 + (2*4*x) + 4^2

       = √(x + 4)^2

       =x + 4

side = x + 4 units