Math, asked by shubh4247, 1 month ago

The area of the square that can can be inscribed in a circle of radius 8 cm is​


ay740292: Let ABCD be the square inscribed by the circle.

∴OA=OB=OC=OD

ABC is a right angled triangle, as OA=8,OB=8

AB=8+8=16

According to Pythagoras theorem,

Square of hypotenuse = Sum of squares of other two sides.

AC2=AB2+BC2

As ABCD is a square all the sides are equal, AB=BC

AC2=2AB2

162=2AB2

∴AB=82​

therefore side of the square =82​

Area of square =(82​)2=128cm2

Answers

Answered by pazhaniakshaiadhi
2

Question : The area of the square that can can be inscribed in a circle of radius 8 cm is

Answer :

Given that : Radius = 8 cm

Formula used : Pythagoras Theorem

Let ABCD be the square inscribed by the circle.

∴OA=OB=OC=OD

ABC is a right angled triangle, as OA=8,OB=8

AB=8+8=16

According to Pythagoras theorem,

Square of hypotenuse = Sum of squares of other two sides.

AC2=AB2+BC2

As ABCD is a square all the sides are equal, AB=BC

AC2=2AB2

162=2AB2

∴AB=82

therefore side of the square =82

Area of square =(82)2=128cm

Hopes it helps you

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