Math, asked by rajsnehdeep8, 3 months ago

The area of the surface of the part of y^(2)+z^(2)=x^(2) cut off by the cylinder x^(2)- y^(2)=a^(2) and the planes y=b y=-b is a.2sqrt(2)ab b.4sqrt(2)ab c.8sqrt(2)ab d.none of these​

Answers

Answered by srijayantpanigrahi20
0

Step-by-step explanation:

The area of the surface of the part of y^(2)+z^(2)=x^(2) cut off by the cylinder x^(2)- y^(2)=a^(2) and the planes y=b y=-b is a.2sqrt(2)ab b.4sqrt(2)ab c.8sqrt(2)ab d.none of these

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