Physics, asked by akatepallewar, 9 months ago

The area of the tip of a screw Is 0.5 mm^2 and it's weight is 0.5 N. Calculate the pressure( in pa ) exerted by the screw on a wooden plank.

Answers

Answered by shrinijarvis
24

area of tip = 0.5mm^2

converting mm^2 to m^2.

first we convert mm^2 to cm^2 and then to m^2

0.5 * \frac{1}{10}* \frac{1}{10} cm^2 = 0.5 * \frac{1}{100} cm^2

=>   0.5 * \frac{1}{100} cm^2 => 0.5 * \frac{1}{100} * \frac{1}{100} * \frac{1}{100} m^2

=> 0.5 * \frac{1}{1000000} = 0.5 * \frac{1}{10^6} = 0.5 * 10^{-6}m^2

pressure = force / area

=> \frac{0.5}{0.5 * 10^{-6}} => \frac{1}{10^{-6}} => 10^6 pascals

the pressure is 10^6 pascals

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Answered by hamneravindra
0

Answer:

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