Question

The area of the tip of a screw Is 0.5 mm2 and it's weight is 0.5 N. Calculate the pressure( in pa ) exerted by the screw on a wooden plank

Answer 1

Explanation:

as we know that, pressure =force/area

area of tip of screw = o.5 mm=0.5/1000=0.0005m

force=weight of screw=0.5N

pressure = 0.5/0.0005=1000pa

Answer 2

Answer:

The pressure exerted by screw on the wooden plank is

${10}^{6} Pa$

Explanation:

Given that,the Area of tip of the screw is 0.5sq.mm

$=>A=0.5mm^{2} = 0.5 \times 10 {}^{ - 6} {m}^{2} \\ = 5 \times {10}^{ - 7} {m}^{2}$

Also given the weight of the screw is 0.5N.Weight is nothing but force exerted by tip of the screw on the wooden plank.We are required to find the pressure exerted by screw on wooden plank.The pressure exerted is the ratio of force exerted to area.Mathematically,

$P=\frac{F}{A}$

Substituting the values of force and area in above relation,we get

$P=\frac{0.5}{5 \times 10 {}^{ - 7} } = {10}^{6} \: P a$

Therefore,the pressure exerted by screw on the wooden plank is

${10}^{6} \: pa$

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