Question

THE AREA OF THE TRAPEZIUM FORMED BY THE LINES X=0,X=2,Y=4 AND X+Y=2

Answer 1

The area of the trapezium will be 6 sq, units.

Step-by-step explanation:

The lines x = 0 and x = 2 are y-axis and parallel to y-axis.

The lines y = 4 is parallel to x-axis and x + y = 2 has x-intercept at (2,0) and y-intercept at (0,2).

Now, line x + y = 2 crosses x = 2 line at (2,0) and crosses x = 0 at (0,2) point.

So, the trapezium formed by those four lines has parallel sides lengths (4 - 0) = 4 units and (4 - 2) = 2 units.

And the height of the trapezium is (2 - 0) = 2 units.

Therefore, the area of the trapezium will be \frac{1}{2}(4 + 2)(2) = 6

2

1

(4+2)(2)=6 sq, units. (Ans

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Answer 2

Answer:

Step-by-step explanation:

The area of the trapezium will be 6 sq, units.

Step-by-step explanation:

The lines x = 0 and x = 2 are y-axis and parallel to y-axis.

The lines y = 4 is parallel to x-axis and x + y = 2 has x-intercept at (2,0) and y-intercept at (0,2).

Now, line x + y = 2 crosses x = 2 line at (2,0) and crosses x = 0 at (0,2) point.

So, the trapezium formed by those four lines has parallel sides lengths (4 - 0) = 4 units and (4 - 2) = 2 units.

And the height of the trapezium is (2 - 0) = 2 units.

Therefore, the area of the trapezium will be \frac{1}{2}(4 + 2)(2) = 6

2

1

(4+2)(2)=6 sq, units. (Ans ]