Question

The area of the trapezium , if the parallel sides are measuring 8 cm and 10 cm and the height 5 cm is​

Answer 1

Given :

• Parallel sides of a trapezium are 8 cm and 10 cm.
• Height of Trapezium is 5 cm.

To Find :

• Area of Trapezium.

Solution :

$\longmapsto\tt{Parallel\:Sides=8cm\:and\:10cm}$

$\longmapsto\tt{Height=5\:cm}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Trapezium=\dfrac{1}{2}\times{(Sum\:of\:Parallel\:Sides)}\times{h}}$

Putting Values :

$\longmapsto\tt{\dfrac{1}{2}\times{(8+10)}\times{5}}$

$\longmapsto\tt{\dfrac{1}{{\cancel{2}}}\times{{\cancel{18}}}\times{5}}$

$\longmapsto\tt{9\times{5}}$

$\longmapsto\tt\bf{45\:{cm}^{2}}$

So , The Area of Trapezium is 45 cm²...

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Properties of Trapezium :

• Diagonals of a Trapezium bisects each other.
• A trapezium has two non-parallel and two parallel sides.
• Sum of all angles of a trapezium is 360°.

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Answer 2

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$\rm\boxed\checkmark$ $\textsf{\textbf{\blue{Given :-}}}$

• Parallel sides = 8cm and 10cm.

• Height = 5cm.

$\rm\boxed\checkmark$ $\textsf{\textbf{\blue{To Find:-}}}$

• Trapezium Area

$\rm\boxed\checkmark$ $\textsf{\textbf{\blue{Solution :-}}}$

Formula,

$\implies {\sf{Area \: of \: Trapezium = \dfrac{1}{2} × (Sum \: of \: Parallel \: Sides) × h}}$

Values :-

$\implies{\sf\dfrac{1}{2} \times (8 + 10) \times 5}$

$\implies{\sf\dfrac{1}{\cancel{2} }\times \cancel{18} \times 5}$

$\implies{\sf{9 \times 5}}$

$\implies{\textsf{\textbf{45cm²}}}$

• Area = 45cm².

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