Question

the area of the trapezium is 105 CM square and its height is 7 cm if one of the parallel sides is longer than the other by 6 cm find the two parallel sides

Answer 1

Let the side 'x'

Area of trapezium = 1/2 × sum of parallel sides × height

105 = 1/2 × ( x + x+6 ) × 7
105/7 = 1/2 × ( 2x + 6 )
15 × 2 = 2x + 6
30 = 2x + 6
30 - 6 = 2x
24 = 2x
x = 12 cm .

=> x = 12 cm
=> x+6 = 12 + 6 = 18 cm.

=> The length of one side is 12 cm.
=> The length of second side is 18 cm.

Answer 2

Step-by-step explanation:

area of a Trapezium = 105 cm^2

let one of the parallel sides be x cm

than other parallel side will be (x+6)cm

height = 7cm

area of trapezium= 1/2 (sum of ll sides) h

= 1/2(x+x+6)7= 105

2x+6= 105×2/7

2x= 30-6

x= 24/2

x= 12

x+6= 12+6= 18

hence,

parallel sides of trapezium are 12cm and 18cm.