The area of the trapezium is 180centimetres² and it's height is 9 centimetres. If one of the parallel side is longer than the other by 6centimetres,find the two parallel side.
Answers
Given :-
- Shape = Trapezium
- Area of the Trapezium = 180cm²
- Height of the Trapezium = 9cm
- One of the Parallel Side is longer than the other by 6cm
To Find :-
- The Two Parallel Sides of the Trapezium.
Solution :-
➟ Let the First Side be x cm
➟Then the Second Side will be x+6cm
According to the Question :
➞ Area = ½ × Height × Sum of Parallel Sides
➞ 180 = ½ × 9 × ( x + x + 6 )
➞ 180 / 9 = ½ × 2x + 6
➞ 20 = ½ × 2x + 6
➞ 20 × 2 = 2x + 6
➞ 40 = 2x + 6
➞ 40 - 6 = 2x
➞ 34 = 2x
➞ 34 / 2 = x
➞ 17cm = x
_______________
Therefore :-
- First Side = x = 17cm
- Second Side =x+6=17+6= 23cm
_______________
Verification :-
⟾ ⠀Area =½×Height×Sum of Sides
⟾ ⠀⠀Area = ½ × 9 × ( 17 + 23 )
⟾ ⠀⠀Area = ½ × 9 × 40
⟾ ⠀⠀Area = 9 × 20
⟾ ⠀⠀180 = 180
_______________
Answer:
➟ Let the First Side be x cm
➟Then the Second Side will be x+6cm
According to the Question :
➞ Area = ½ × Height × Sum of Parallel Sides
➞ 180 = ½ × 9 × ( x + x + 6 )
➞ 180 / 9 = ½ × 2x + 6
➞ 20 = ½ × 2x + 6
➞ 20 × 2 = 2x + 6
➞ 40 = 2x + 6
➞ 40 - 6 = 2x
➞ 34 = 2x
➞ 34 / 2 = x
➞ 17cm = x
_______________
Therefore :-
First Side = x = 17cm
Second Side =x+6=17+6= 23cm
_______________
Verification :-
Area =½×Height×Sum of Sides
Area = ½ × 9 × ( 17 + 23 )
Area = ½ × 9 × 40
Area = 9 × 20
180 = 180
Hence Verified ✓