Question

The area of the trapezium is 210 cm² and its height is 14 cm. if one of the parallel sides is longer than the other by 6 cm,find the parallel sides.

Answer 1

let the two parallel side be x and x+6 then

$area = \frac{1}{2} (sum \: of \: parallel \: side \: ) \times height \\ \\ 210 = \frac{1}{2} (x + x + 6) \times 14 \\ \\ 210 = 14x + 42 \\ \\ 168= 14x \\ \\ x = 12$

sides are of : 12cm and 18cm

Answer 2

hola!

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The area of the trapezium is 210 cm² and its height is 14 cm. if one of the parallel sides is longer than the other by 6 cm,find the parallel sides.

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here is the solution...........

The area of the trapezium is 210 cm²

height is 14 cm

ATQ,

if one of the parallel sides is longer than the other by 6 cm

let the smaller one be a

bigger side = a+6

so,

1/2(a+a+6)14 = 210

14(2a+6) = 210*2

28a+84 = 420

28a = 420-84

28a = 336

a = 336/28

a = 12

other side = a+6 = 12+6 = 18cm

so the parellel sides are 12cm and 18cm

hope it helps u..........

:)

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