Question

the area of the trapezium is 336 sq.cm. if. it's parallel sides are Inthe ratio 5:7 and the perpendicular distance between them be 14 cm then the smaller of parallel sides is​

Answer 1

Answer:

20cm

Step-by-step explanation:

area of trapezium = $\frac{1}{2} * sum of parallel sides* height$

let the ratio of parallel sides = 5x:7x

336 = $\frac{1}{2}$*(5x+7x)*14

336*2/14=12x

48 = 12x

x = 48/12

x = 4

smaller side of trapezium = 5*4 = 20cm

Answer 2

Answer:

10cm ..................

EXPLANATION

ar of trep. = 1/2*sum of // side * distance b/w them

so

336 = 1/2*5k + 7k * 14 (let sides be 5k and 7k

smaller and bigger resp. )

336 = 1/2*12k * 14

336 = 1/2*168k

k = 4cm

so

smaller side = 5k

= 5*4

= 20cm