Question

. The area of the trapezium is 912 cm square .The length of its parallel sides are in the ratio 6:13 and the height is 24 cm .Find the lengths of the parallel sides.

Answer 1

Solution :-

Let the ratio of parallel sides of trapezium be a part of x

Then the sides will be

• 6x

• 13x

Now , as we know that

Area of trapezium = ½ × (sum of parallel sides) × Height

➩ 912 = 1/2 × (6x + 13x) × 24

➩ 912 × 2 = 19x × 24

➩ 1824 ÷ 24 = 19 x

➩ 76 = 19x

➩ 76 ÷ 19 = x

➩ x = 4

_________________________

Now , finding the parallel sides

➨ 6x

➨ 6(4)

➨ 24 cm

_______________

➥ 13x

➥ 13(4)

➥ 52 cm

_________________________

Hence , length two parallel sides = 24 cm & 52 cm .

Answer 2

Answer:

DATA GIVEN:

AREA OF TRAPEZIUM = 912 CM SQUARE.

LENGTH IF THE PARALLEL SIDES ARE IN THE RATIO 6:13.

HEIGHT =24 CM.

TO FIND:

LENGTHS OF THE PARALLEL SIDES.

FORMULA USED:

$(sum \: of \: parallel \: sides) \times h \times \frac{1}{2} = \frac{sum \: of \: parallel \: sides \: \times h}{2}$

SOLUTION:

LET THE PARALLEL SIDES BE 6X AND 13 X.

AREA OF TRAPEZIUM = SUM OF PARALLEL SIDES×H/2

=>912 =(6X+13X)×24/2

=>912×2=19X×24

=>1824=456X

=>X=1824/456=4

WE GOT X=6

NOW 6X=6×4=24 CM

13X=13×4=52 CM

HENCE LENGTH OF PARALLEL SIDES ARE 24 CM AND 52 CM.