Question

the area of the triangle enclosed between the coordinate axes and the line passing through [8,-3] and [-4,12] is

Answer 1

first make the equation of line then..get the y and x coordinates where it cuts coordinate axes then take one as base another as height and put it in formula of area of Δ

Answer 2

CONCEPT

TWO POINT FORM

GIVEN

X1=8, X2=-3

Y1=-4, Y2=12

FIND

between the coordinate axes and the line passing through [8,-3] and [-4,12]

SOLUTION

BY TWO POINT FORM

Y-Y1=Y2-Y1 / X2-X1 × X-X1

Y+3=12+3/-4-8× X-8

-12(Y+3)= 15X-120

-12Y-36=15X-120

15X+12Y-84=0

NOT PUT X=0 BY CUTTING Y AXIS

Y=84÷12

Y=7 (HEIGHT)

NOW PUT Y=0 AND CUT X AXIS

X=84÷15

X=28÷5 (BASE)

NOW AREA = 1/2×28÷5×7

AREA = 98÷5 SQUARE UNIT

HENCE THE AREA IS 98 BY 5 SQUARE UNIT.

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