Question

the area of the triangle formed by the line 3x+4y-12=0 and co ordinate axes is=?​

Answer 1

$\maltese$$\tt{solution:-}\maltese$

the equation of line is 3x+4y-12=0

Dividing the equation both side by 2

then,

$\rightarrow \tt\frac{3x}{12}+\frac{4y}{12}=\frac{12}{12}\\ \rightarrow \tt \frac{x}{4}+\frac{y}{3}=1\\ \tt Area\:of\:the\: triangle=\frac{1}{2}×base×height\\ \rightarrow\tt\frac{1}{2}×4×2\\ \rightarrow \tt{\underline{\fbox{6 sq.unit}}}$