Question

The area of the triangle formed by the line 5x-3y+10=0 with co-ordinate axis will be

Answer 1

first of all let's find the points where the line ID cutting X and y axis
for X axis : y=0
$5x - 3y + 10 = 0 \\ 5x = - 10 \\ x = - 2 \\ \\ for \: y \: \: axis \: x = 0 \\ - 3y = - 10 \\ y = \frac{10}{3} \\ so \: area \: = | \frac{1}{2} b \times h | \\ = | \frac{1}{2} \times ( - 2) \times \frac{10}{3} | \\ = \frac{10}{3} {unit}^{2}$
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