Question

the area of the triangle formed by the lines 5x+7y=35 with the coordinate axis​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

The area of the triangle formed by the lines 5x+7y=35 with the coordinate axis

CALCULATION

Here the given equation of the line is

$\sf{5x + 7y = 35}$

Which can be rewritten as

$\displaystyle \sf{ \frac{5x}{35} + \frac{7y}{35} = 1 \: }$

$\implies\displaystyle \sf{ \frac{x}{7} + \frac{y}{5} = 1 \: }$

Which is of intercept form

Thus the line cuts the X axis at A ( 7 , 0 ) and Y axis at B( 0, 5 )

The triangle formed by the given line and the coordinate axes is OAB.

GRAPH : The graph is referred to the attachment

CALCULATION OF AREA

The triangle is is a right angled triangle

Where base = OA = 7 unit

Height = OB = 5 unit

Hence the area of the triangle is

$= \displaystyle \sf{ \frac{1}{2} \times 7 \times 5} \: \: \: \: \: sq .unit$

$= \displaystyle \sf{ \frac{35}{2} } \: \: \: \: \: sq .unit$

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4x+3y=48 with coordinate axes.

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