The area of the triangle formed by the points (5,2),(-9,-3),(-3,-5)
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here,
- x1 = 5, x2 = -9, x3 = -3
- y1 = 2, y2 = -3, y3 = -5
substituting values in the formula,
area
= 1/2(5(-3-(-5) + (-9)(-5-2) + (-3)(2-(-3)
= 1/2(5(-3+5) -9(-5-2) -3(2+3)
= 1/2(5(2) -9(-7) -3(5)
= 1/2(10 + 63 - 15)
= 1/2(58)
= 29
__________________________
Area of traingle = 29 sq. units
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