Question

the area of the triangle formed by the points by using heron formula (1,1) ,(1,4)and (5,1) please solve the answer ​

Answer 1

Answer:

Let A(x1,y1)=(1,1) B(x2,y2)=(1,4) C(x3,y3)=(5,1) By using distance formula , AB = √[0+9] =3units. BC = √[16+9] =5units. AC = √[16-0] =4units

1 answer

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:area = 6

The length and breadth of triangle is 4cm and 3 cm respectively.

hypotenuse = $\sqrt{l^2 + b^2}$

                    = $\sqrt{4^2 + 3^2}$

                    = $\sqrt{16 + 9}$

                    = $\sqrt{25}$

                    = 5cm

half perimeter = (3+4+5)/2

                     s = 12/2

                     s = 6cm

area = $\sqrt{s(s-l)(s-b)(s-h)}$

area = $\sqrt{6(6-4)(6-3)(6-5)}$

area = $\sqrt{6*2*3*1}$   [* is multiplication sign]

area = 6 [ we divide 6 into 2 and 3 and take both common. so we take 2 and 3 out of the root]

HOPE IT HELPS!!!!